Question

(x+1) is a factor of the polynomial p(x) = x^3 +5x^2+7x+2​

Answer 1

Answer:

x3 + 4x2 - 5x - 14 = (x - 2)q(x), where q(x) is some other polynomial. How could we ... c is a zero of p if and only if (x - c) is a factor of p(x).

Answer 2

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★⟩ To check : whether (x+1) is a factor of

p(x) = x³ + 5x² + 7x + 2

★ ⟩ Solution :

If , (x+1) is a factor of p(x) then ,

↣ x+1 = 0

↣ x = -1

x = -1 will make the Polynomial = 0

➜ x³ + 5x² + 7x + 2

➜ (-1)³ + 5(-1)² + 7(-1) + 2

➜ -1 + 5 - 7 + 2

➜ 4 - 5

➜ - 1 ≠ 0

So , it is not a factor of p(x)