Question

(x+1) is a factor of x^2 +ax+2 then value of a​

Answer 1

x+1=0

x=-1

p(x)=x^2+ax+2

p(-1)=(-1)^2+a×-1+2

=1-a+2

a=1+2=3

Answer 2

$p(x) = {x}^{2} + ax + 2 \\ x + 1 = 0 \\ x = - 1 \\ ( - 1) {}^{2} + a( - 1) + 2 = 0 \\ 1 - a + 2 = 0 \\ 3 - a = 0 \\ a = 3$