Question

(x +1) is a factor of x^n + 1 only if *

Answer 1

Answer:

(x+1) is a factor of xⁿ+1 only if n is odd.

In that case, the factorization goes

 xⁿ+1 = (x+1)(xⁿ⁻¹ - xⁿ⁻² + xⁿ⁻³ - ... + x² - x + 1)

Hope that helps.