Question

x-1 is a factor of x3-3x2+7x+b find​

Answer 1

Answer:

⁹

Step-by-step explanation:

Answer:

(x - 1)( {x}^{2} - 2x + 5)(x−1)(x

2

−2x+5)

Step-by-step explanation:

It is given that,

{x}^{3} - 3 {x}^{2} + 7x - 5x

3

−3x

2

+7x−5

It is 3 degree polynomial, so we can apply hit and trial method to find one factor.

Lets put the value x = 1 in the polynomials.

= {1}^{3} - 3 \times {1}^{2} + 7 \times 1 - 5=1

3

−3×1

2

+7×1−5

= 1 - 3 + 7 - 5=1−3+7−5

= 0=0

It equals to zero, therefore (x-1) is a factor of this polynomials.

So dividing the given polynomials by (x-1) ,

we get,

{x}^{3} - 3 {x}^{2} + 7x - 5x

3

−3x

2

+7x−5

= (x - 1)( {x}^{2} - 2x + 5)=(x−1)(x

2

−2x+5)

After observing, we see that

further, it is not factorisable.

Hence, the factorisation is ,

(x - 1)( {x}^{2} - 2x + 5)(x−1)(x

2

−2x+5)

Note :- Refer to the attachment

Answer 2

hope it helps you

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