(x+1) is a factor of xn + 1 only
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x+1 is a factor of xn+1 only if. [a] n is an odd integer. [b] n is an even integer. [c] n is a negative integer.
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Answer:
n is an odd number
Step-by-step explanation:
We have,
Let, h is odd number xn+1 can be factorised as (x+1)(1 − x + x2 = x3 +.....xn − 1)
This (x+1) is a factor
Take p(x)=xn+1
When n is odd, we get, p(−1)=−1+1=0
(x+1) is a factor of p(x).
Hence, this is the answer.
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