Question

x+1 is the factor of polynomail ​

Answer 1

Answer:

ur first question is wrong

Step-by-step explanation:

b)First, group the two terms on the left and the two terms on the right as:

(x^3+x^2)+(x+1)

Now, factor out an x^2 from the term on the left to give:

[(x^2*x)+(x^2*1)]+(x+1)

x^2(x+1)+1(x+1)

now the factors are (x^2+1)(x+1)

a)Given: (x + 1),  (x^3 + x^2 - x - 1).

To find: Whether (x + 1) is a factor of  (x^3 + x^2 - x - 1).

Answer:

Using factor theorem x + 1 = 0.

x = 0 - 1

x = -1

Let p(x) =  (x^3 + x^2 - x - 1).

p(-1) = ((-1)^3 + (-1)^2 - (-1) - 1)

p(-1) = -1 + 1 + 1 - 1

p(-1) = 0

Therefore, (x + 1) is a factor of  (x^3 + x^2 - x - 1).