x+1 is the factor of x²+ax+2 then value of a is;
(a) 4
(b) -3
(c) 2
(d)3
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Given,
x + 1 = 0 (Since x+1 is a factor)
⟹ x = -1
Putting x = -1 in the equation
x² + ax + 2 = 0
⟹ (-1)² + a × (-1) + 2 = 0
⟹ 1 + (-a) + 2 = 0
⟹ 3 - a = 0
⟹ -a = -3
⟹ a = 3
Therefore, (D) is the correct option.
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