Math, asked by passwod54991, 3 months ago

(x-1) isa factor of x3-7x2+14x-8

Answers

Answered by tummakeerthana19
1

Answer:

x-1)x³-7x²+14x-8(x²-6x+8

-(x³-1x²)

-6x²+14x

-(6x²+6x)

8x-8

- (8x-8)

0

quotient=x²-6x+8

remainder =0

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