x + 1 + iy = 4 +3i find value of x And y
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Answer:
(x+1) + iy = 4 + 3i
Comparing real and imaginary parts
x + 1 = 4 and iy = 3i
x = 4 - 1 and y =3
x = 3
The value if x and y is 3 and 3
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x(1+ 2i) + y( 2-i) = 4 + 3i
Let us expand the brackets.
==> x + 2xi + 2y - yi = 4 + 3i.
==> We will combine real terms and complex terms together.
==> (x+ 2y) + (2x -y) i = 4 + 3i.
Now we will compare terms.
==> x + 2y = 4 ..............(1)
==> 2x - y = 3 ....................(2)
Now we will solve the system.
We will use the substitution method to solve.
==> We will rewrite y= 2x - 3.
==> x+ 2y = 4
==> x + 2(2x-3) = 4
==> x + 4x - 6 = 4
==> 5x = 10
==> x= 2.
==> y= 2x -3 = 2*2 - 3 = 4-3 =1
==> y= 1
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