Question

x^(1+ log base 10 x)=10x​

Answer 1

I hope this is the answer.

I tried this solution int this way..

Answer 2

Answer:  $x = 10$ or $\frac{1}{10}$

Step-by-step explanation:

Given, $x^{1+log_{10}x } = 10x$

⇒ $x^1 * x^{log_{10}x} = 10 * x$

⇒ $x = 10^{\frac{1}{log_{10}x}$

⇒ $x = 10^{log_x10}$

Let us assume $x = 10^y$ for some value of y

⇒ $10^y = 10^{log_{10^y}10}$

⇒ $y = log_{10^y}10^1$

⇒ $y = \frac{1}{y}$

⇒ $y^2 = 1$

⇒  $y =$ ±1

∴ $x = 10^y = 10^1$ or $10^{-1}$

⇒ $x = 10$ or $\frac{1}{10}$