x^(1+logxbase10)=10x
golu46:
what to do..solve or prove
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x^{ 1 + log(x base 10)} = 10x
take both sides log wih base 10
log{x base 10} { 1 + log(x base 10)} = log{10x base 10}
log{x base 10} { 1 + log(x base 10)} = 1 + log(x base 10)
Let, log{ x base 10} = P
P( 1 + P) = (1 + P)
(P -1) (1 + P) = 0
P = 1 , -1
log{x base 10} = 1 and -1
x = 10 and 1/10
take both sides log wih base 10
log{x base 10} { 1 + log(x base 10)} = log{10x base 10}
log{x base 10} { 1 + log(x base 10)} = 1 + log(x base 10)
Let, log{ x base 10} = P
P( 1 + P) = (1 + P)
(P -1) (1 + P) = 0
P = 1 , -1
log{x base 10} = 1 and -1
x = 10 and 1/10
abhi .plz answer my second question too
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