x=1 p(x)=5x^2-3x+7
find the value now
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X=4
p(X)=5x^2-3x+7
substitute 1 in the place of X
then,
p(1)=5(1)^2-3*1+7
p(1)=5*1-3+7
p(1)=5-3+7
p(1)=9
therefore the value of 5x^2-3x+7=9
p(X)=5x^2-3x+7
substitute 1 in the place of X
then,
p(1)=5(1)^2-3*1+7
p(1)=5*1-3+7
p(1)=5-3+7
p(1)=9
therefore the value of 5x^2-3x+7=9
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