Question

x^1/p+y^1/q+z^1/r and xyz=1 then the value of p+q+r=?

Answer 1

Let, $x^{1/p}= y^{1/q} = z^{1/r} =k$
Then,
$x^{1/p}=k$
or,$( x^{1/p}) ^{p}$=$k^{p}$ 
or, x=$k^{p}$
Similarly, $y= k^{q}$ and $z=k^{r}$
∵, xyz=1
∴, $k^{p} k^{q} k^{r}$ = 1
or, $k^{p+q+r}$=$k^{0}$
or, p+q+r=0

Answer 2

Answer:

The answer is

p+q+r = 0