Question

X=(1=root 3 and y=1-root 3 than x^2 +y^2

Answer 1

You do many mistakes but here's your

Answer:

Given:

$x = 1 + \sqrt{3} \\ y = 1 - \sqrt{3} \\ {x}^{2} + {y}^{2} = what$

Solution:

${x}^{2} + {y}^{2} \\ = (1 + \sqrt{3} ) ^{2} + (1 - \sqrt{3} ) ^{2} \\ = (1 + {3}^{ \frac{1}{2} \times 2 } ) + (1 - \sqrt{3} ^{ \frac{1}{2} \times 2} ) \\ = (1 + 3 + 1 - 3) \\ = 2$

Requeste:

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