x=1/root 5 - root 2 find x square
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Given
x = 1/√5 - √2
x = 1 - √2 ( √5 ) / √5
x = 1 - √10 / √5
Rationalising factor of √5 is √5
Now by rationalising the denominator, we get
x = ( 1 - √10 ) √5 / √5( √ 5 )
x = √5 - √50 / 5
√50 simplifies to 5√2
x = √5 - 5√2 / 5
Now squaring b/s, we get
(x)^2 = [ ( √5 - 5√2 )/ 5 ] ^2
See I am simplifying this part quickly and giving you a directly simplifies expression
x^2 = 5 + 50 - 10√10 / 25
x^2 = 55 - 10√10 / 25
x^2 = 5( 11 - 2√10) / 5(5)
x^2 = 11 - 2√10 / 5
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