Question

x+1=root over of 2 (1-x) solve
plz answer this​

Answer 1

Answer:

x+1=√{2(1-x)}

(x+1)^2=2(1-x)

=> x^2+2x+1=2-2x

=> x^2+2x+2x+1-2=0

=> x^2+4x-1=0

=> x^2+4x+4-5=0

=> (x+2)^2-(√5)^2=0

=> (x+2+√5)(x+2-√5)=0