Question

x+1
${2x}^{3} - x {}^{2} - 13x - 6$
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Answer 1

Answer:

${2x}^{3} - {x}^{2} - 13x - 6$

Here. at x = -2 given function become zero hence x+2 is a factor.

${2x}^{2} (x + 2) - 5x(x + 2) - 3(x + 2) \\ \\ = (x + 2) [2 {x}^{2} - 5x - 3 ] \\ \\ = (x + 2)(2 {x}^{2} - 6x + x - 3) \\ \\ = (x + 2)(2x(x - 3) + 1(x - 3)) \\ \\ = (x + 2)(2x + 1)(x - 3)$