Math, asked by guptasm00000, 4 months ago

(X + 1 upon 2 X) whole to the power2

Answers

Answered by Karamjotkaur
0

Answer:

 {(x +   \frac{1}{2x} )}^{2}  =  {x}^{2}  +  \frac{1}{4 {x}^{2}  }  + 1 \\  =  \frac{4 {x}^{4}  + 1 + 4 {x}^{2} }{4 {x}^{2} }

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