(x+1 upon x) (x-1 upon x) =
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To find :(x+1/x)(x-1/x)
By using identity (a+b)(a-b)=a^2-b^2
=>(x+1/x)(x-1/x)=(x)^2-(1/x)^2
= x^2-1/x^2
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(x+1/x)(x-1/x)=(a+b)(a-b)
(a+b)(a-b)=a^2-b^2
(x+1/x)(x-1/x)=x^2-1/x^2
(a+b)(a-b)=a^2-b^2
(x+1/x)(x-1/x)=x^2-1/x^2
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