Question

x-1-(x-1)^2+4-4x factorise​

Answer 1

x-1-x^2-1+2x+4-4x

=-x^2-x+2

=x^2+x-2

=x^2+2x-x-2

=x(x+2)-1(x+2)

=(x-1)(x+2)

x=1,-2

Hey mate here is your Answer

Hope this helps

Answer 2

Answer:

$x - 1 - ( {x - 1)}^{2} + 4 - 4x = 0\\ x - 1 - ( {x}^{2} + 1 - 2x) + 4 - 4x = 0\\ x - 1 - {x}^{2} - 1 + 2x + 4 - 4x = 0\\ - {x}^{2} - x + 2 = 0 \\ {x}^{2} + x - 2 = 0 \\ {x}^{2} + 2x - x - 2 = 0 \\ x(x + 2) - 1(x + 2) = 0 \\ (x + 2)(x - 1) = 0$

$x = 1 \: and \: - 2$

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