Question

x-1 -(x-1)^2+4-4x solve.............,.......................

Answer 1

the first step we rearrange the terms of the decreasing order of their power then in the middle time we multiply by opening the brackets then the 4th Stp we expand the first time using a minus b the whole square then finally getting a equation then for changing the sign of the first time or the extra time we multiply it with minus and finally we get the value of x hope you get the answer correct thanks anyway thanks for your question

Answer 2

The solution is x=-2,1.

Step-by-step explanation:

Given : Expression $x-1 -(x-1)^2+4-4x$

To find : Solve the expression ?

Solution :

Write expression as equation to solve,

$x-1 -(x-1)^2+4-4x=0$

$x-1-(x^2+1^2-2x)+4-4x=0$

$x-1-x^2-1^2+2x+4-4x=0$

$-x^2-x+2=0$

$x^2+x-2=0$

Solve by middle term split,

$x^2+2x-x-2=0$

$x(x+2)-1(x+2)=0$

$(x+2)(x-1)=0$

$x=-2,1$

Therefore, the solution is x=-2,1.

#Learn more

Factorize the following: x -1-(x-1)square =4-4x

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