Question

(x - 1), (x + 1) and (x – 3) are factors of f(x) = x3 - ax2 + bx + 3 find a & b​

Answer 1

11111111¹11111111(3(838_738₹(+₹+(₹++₹+₹+₹(2(1)2)1)2#))2(3(3(₹+3+₹+;4(2))1

Answer 2

Answer:

a = 3 & b = -1

Step-by-step explanation:

Finding Zeros from Factors

$x - 1 = 0\\ x = 1$

α = 1

$x + 1 =0\\x = -1$

β = -1

$x - 3 = 0\\ x= 3$

γ = 3

Using Formulas of Cubic Polynomials

-(square term's coeff.)/(cube term's coeff.) = α + β + γ

$-(-a)/1 = 1 +(-1) + 3$

a = 3

(linear term's coeff.)/(cub1 term's coeff.) = αβ + βγ + γα

$b/1 = (1)(-1) + (-1)(3) + (3)(1)\\b = -1 -3 + 3$

b = -1