Math, asked by nikhilkashyap8447386, 2 months ago

x-1/x+1
kavalan Pratham Siddhant ke anusar
x - 1 \x + 1

Answers

Answered by Anonymous
3

Answer:

 \dfrac{ {x}^{2} + 1 - 2x }{ {x}^{2}  - 1}

Step-by-step explanation:

Rationalising the denominator

 \dfrac{x - 1}{x + 1}  \times  \dfrac{x - 1}{x - 1}  \\  \\  \dfrac{ {(x - 1)}^{2} }{(x + 1)(x - 1)}  \\  \\  \dfrac{ {x}^{2} + 1 - 2x }{ {x}^{2}  - 1}

Hope it helps u

Similar questions