Math, asked by gamingwithchotu8, 5 hours ago

(x+1)(x-1)(x^2+1)(x^4+1) use this identity (a+b)(a-b)=a^2-b^2 please tell me fast ⏩​

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Answered by MonaVNV
1

Answer:

x^8 - 1

Step-by-step explanation:

= (x^2 - 1)(x^6 + x^4 + x^2 +1)

= x^8 + x^6 + x^4 + x^2 - x^6 - x^4 - x^2 - 1

= x^8 + (x^6 - x^6) + (x^4 - x^4) + (x^2 - x^2) - 1

=x^8 - 1

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