Math, asked by gurleen2000hspur, 16 days ago

(x+1)(x-1)+(x-2)/(x+2)=3 where x is not equal to 1 or -2​

Answers

Answered by shrabantijana5811
1

Answer:

(x+1)(x-1)+(x-2)/(x+2)=3

Or, x^2-1+x^2-4-3=0

or, 2x^2-8=0

Or x^2-4=0

or, (x-2)/(x+2)=0

since x is not equal to-2.

so, (x-2) =0

or, x=2

Hence, the value of x is 2.

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