Question

X+1/x-1 + x-2/x+2 = 4 - 2x+3/x-2 solve this equation for x?

Answer 1

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Answer 2

The value of x is 11/9

Step-by-step explanation:

Given : $\frac{x+1}{x-1}+\frac{x-2}{x+2}=4-\frac{2x+3}{x-2}$

To Find : Value of x

Solution:

$\frac{x+1}{x-1}+\frac{x-2}{x+2}=4-\frac{2x+3}{x-2}\\\frac{(x+1)(x+2)+(x-1)(x+2)}{(x-1)(x+2)}=4-\frac{2x+3}{x-2}\\\frac{x^2+3x+2+x^2+x-2}{(x-1)(x+2)}=4-\frac{2x+3}{x-2}\\\frac{x^2+3x+x^2+x}{(x-1)(x+2)}=4-\frac{2x+3}{x-2}\\\frac{2x^2+4x}{(x-1)(x+2)}=4-\frac{2x+3}{x-2}\\\frac{2x(x+2)}{(x-1)(x+2)}=4-\frac{2x+3}{x-2}\\\frac{2x}{(x-1)}=4-\frac{2x+3}{x-2}\\\frac{2x}{(x-1)}+\frac{2x+3}{x-2}=4\\\frac{11}{9}=x$

Hence The value of x is 11/9

#Learn more:

Solve the equation: 2(x-3)^2+3(x-2)(2x-3)=8(x+4)(x-4)-1

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