(x-1)(x+1)(x2-1)=0 the set of positive root's of the equation
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According to the question,
(x-1) = 0
X = 1. ... 1
(x+1) = 0
X = - 1 .... 2
(2x - 1) =0
2x = 1
X = 1/2
Therefore, x = 1,1/2.(positive roots of X)
(x-1) = 0
X = 1. ... 1
(x+1) = 0
X = - 1 .... 2
(2x - 1) =0
2x = 1
X = 1/2
Therefore, x = 1,1/2.(positive roots of X)
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