(x+1/x)=15,x^2+1/x^2=?
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0
Answer:
Given, (x-1)/x = 15/4
⇒4(x-1) = 15x
⇒4x - 4 = 15x
⇒4x - 15x = 4
⇒-11x = 4
⇒ x = -4/11 ....eqn. 1
Now,
(x-1)/x = 15/4
Squaring both sides,
⇒{(x-1)/x}^2 = (15/4)^2
⇒(x^2 + 1 -2x)/x^2 = 225/16
On adding 4x/(x^2) both sides and solving, you will get
(x^2 + 1 + 2x)/(x^2) = 225/16 + 4x/(x^2)
Now, SUBSTITUTE THE VALUE OF x WE GOT, IN RHS ONLY from eqn. 1.
And Solve... You will get
⇒(x^2 + 1 + 2x)/(x^2) = 49/16
⇒{(x+1)/x}^2 = (7/4)^2
∴ (x + 1)/x = 7/4 (Ans.)
Answered by
0
Answer:
x²+1/x²=223
Is it Ok☆☆☆☆
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