Question

(x-1)(x+2)=0 find the nature of the roots ​

Answer 1

Hie!!

(x - 1) (x + 2) = 0

(x - 1) = 0 OR (x + 2) = 0

x = 1 OR x = -2

So, The roots are real and unequal/distinguish.

For This Quadratic Equation Descrimnant is > 0.

Answer 2

$(x - 1)(x + 2) \\ = > x {}^{2} + 2x - x - 2 \\ = > x {}^{2} + x - 2 \\ = > ax {}^{2} + bx + c = 0 \\ = > so \: the \: roots \: are \: \\ = > b {}^{2} - 4ac \\ = > 1 {}^{2} - 4 \times 1 \times ( - 2) \\ = > 1 + 8 \\ = > 9 \: and \: \\ = > b {}^{2} + 4ac \\ = > 1 {}^{2} + 4 \times 1 \times ( - 2) \\ = > 1 - 8 \\ = > - 7 \: \: \: \: so \: its \: not \: the \: root \: of \: this \: equation \:$

I hope that helps you