Question

(x-1) (x+2)=0
solve it .. ......​

Answer 1

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$(x - 1)(x + 2)$

$= x(x + 2) - 1(x + 2)$

$= {x}^{2} + 2x - x - 2$

$= {x}^{2} + x - 2$

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Answer 2

Answer:

(x-1) (x+2)=0

(x-1) =0. or (x+2)=0

x=1 or -2

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