Question

x +1 x-2+ = 3 (x#1,-2)
x-1 x +2​

Answer 1

Answer:

$\frac{x + 1}{x - 1} + \frac{x - 2}{x + 2} = 3$

$\frac{(x + 1)(x + 2) + (x - 1)(x - 2)}{(x - 1)(x + 2)} = 3$

${x}^{2} + 3x + 2 + {x}^{2} - 3x + 2 = 3( {x}^{2} + x - 2)$

$2 {x}^{2} + 4 = 3 {x}^{2} + 3x - 6$

${x}^{2} + 3x - 10 = 0$

${x}^{2} + 5x - 2x - 10 = 0$

$x(x + 5) - 2(x + 5) = 0$

$(x + 5)(x - 2) = 0$

$x = - 5 \: \: or \: 2$