Question

(x-1)(x-2)(3x-2)(3x+1)=21​

Answer 1

Answer:

x=

Step-by-step explanation:

(X-1)(3X-2)(x-2)(3x+1)=21

=(3x²-5x+2)(3x²-5x-2)=21 ------------(1)

let,3x²-5x=a---------(2)

[putting 3x²-5x=a in (1)]

so,(a+2)(a-2)=21

so,a²-4=21

a²=25

a=+5 or -5

putting a=+5 in(2)

so,3x²-5x=5

so,3x²-5x-5=0

delta=95

deltaispositive.so 2 real roots

here,x=

$\frac{5 + \sqrt{95} }{6}$

and,x=

$\frac{5 - \sqrt{95} }{6}$

putting 3x²-5x=-5

=3x²-5x+5=0

delta is-95 so no real roots

for this question only 2 roots given above

perfect answer

mark as brainlest