(x-1/x)^2+8(x-1/x)=0 solve by using quadratic formula
Answers
Answered by
1
Put x-1/x=y
y^2 +8y=0
D=8^2 - 4(1)(0)
D=64
y= -8+64^1/2 divide by 2 or - 8-64^1 /2 divide by 2
y= - 8+8 or -8-8/2
y=0 or - 16/2
y=0 or - 8
Now, x-1/x=0 or x-1/x =-8
x-1=0 or x-1=-8x
x=1 or x=-8x+1
x+8x=1
9x=1
x=1/9
y^2 +8y=0
D=8^2 - 4(1)(0)
D=64
y= -8+64^1/2 divide by 2 or - 8-64^1 /2 divide by 2
y= - 8+8 or -8-8/2
y=0 or - 16/2
y=0 or - 8
Now, x-1/x=0 or x-1/x =-8
x-1=0 or x-1=-8x
x=1 or x=-8x+1
x+8x=1
9x=1
x=1/9
Mounikamoparthi:
here in answer i didnt understand after d=64
in quadratic equation. for roots there is a formula x=-b+D^1 /2over2 or x=-b-D^1/2over 2
Similar questions