Math, asked by sejawe1690, 11 months ago

x+1/x=2 find value of x^2+1/x^2

Answers

Answered by sangeetamarothi
1

Answer:

2

Step-by-step explanation:

Given,

x+1/x=2

We know that (a+b)²=a²+2ab+b²

Squaring both the sides,

x²+ 2*X*1/X + (1/x)= 2²

x²+2+1/x²= 4

x²+1/x²=4-2 =2

Hope it helps u :)

Answered by TheNightHowler
1

Answer:

Hello mate✌✌✌

x +  \frac{1}{x}  = 2

Squaring both sides, we get

 {(x +  \frac{1}{x}) }^{2}  =  {(2) }^{2}  \\  {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2.x. \frac{1}{x}  = 4 \\  {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2 = 4 \\  {x}^{2}  +  \frac{1}{ {x}^{2} }  =  4 - 2 \\  {x}^{2}  +  \frac{1}{ {x}^{2} }  = 2

Hope it helps

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