x + 1/x = 2 then x³ + 1/x³ = ?
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Answered by
0
Answer:
Let p (x) = x + 1 / x = 2
= x + 1 = 2x
= 2x - x = 1
or, x = 1.
let g(x) = x^3 + 1/x^3
since, x = 1
therefore,
g (1) = (1)^3 +1 / (1)^3
= 1 + 1 / 1
= 2 / 1
= 2
So, the answer to your question is 2.
You can also make it this way -
x + 1/ x = 2
Cubing both sides, we get -
x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8
= x^3 + 1/x^3 + 3 (x + 1/x) = 8
= x^3 + 1/x^3 + 3 × 2 = 8 (since, x + 1/ x = 2)
= x^3 + 1/x^3 = 8 - 6
or, x^3 + 1/x^3 = 2.
Hope this answer helps you out
Answered by
0
Answer:
so answer is 2
Step-by-step explanation:
p (x) = x + 1 / x = 2
= x + 1 = 2x
= 2x - x = 1
or, x = 1.
let g(x) = x^3 + 1/x^3
since, x = 1
g (1) = (1)^3 +1 / (1)^3 => 1 + 1 / 1
= 2 / 1
=2
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