Question

((x+1)×(x+2)) whole upon x.
is this a polynomial justify​

Answer 1

$\huge \fbox \red{ANSWER}$

if it is a polynomial then it will be equal to 0

A.T.Q

$\frac{(x+1)(x+2)}{x} = 0 \\ {x}^{2} + 2x + x + 2 = 0 \\ {x }^{2} + 3x + 2 = 0 \\ \\ hence \: this \: is \: in \: the \: form \: of \: {a}^{2} + bx + c \\ so \: it \: is \: a \: polynomial$

Answer 2

Answer:

if it is a polynomial then it will be equal to 0

A.T.Q

$\begin{gathered} \frac{(x+1)(x+2)}{x} = 0 \\ {x}^{2} + 2x + x + 2 = 0 \\ {x }^{2} + 3x + 2 = 0 \\ \\ hence \: this \: is \: in \: the \: form \: of \: {a}^{2} + bx + c \\ so \: it \: is \: a \: polynomial\end{gathered} </p><p>x$

(x+1)(x+2) =0

x 2 +2x+x+2=0

x 2 +3x+2=0

a2 +bx+c

so,it is a polynomial.