( x + 1 ) ( x - 2 ) + x = 0
State whether the following quadratic equation has two distinct real roots. Justifyyour answer
Answers
Answered by
24
HEY DEAR YOUR ANSWER IS HERE
___( x + 1 ) ( x - 2 ) + x = 0
x2 - 2x +x -2 +x =0
x2 -2x + 2x - 2= 0
x2 -2 =0
x2 =2
x =+-√2
___( x + 1 ) ( x - 2 ) + x = 0
x2 - 2x +x -2 +x =0
x2 -2x + 2x - 2= 0
x2 -2 =0
x2 =2
x =+-√2
Answered by
3
= x^2 -2x + x - 2 + x
= x^2 - 2x +2x -2
= x^2 -2 = 0
= x = -,+✓2 Ans.
= x^2 - 2x +2x -2
= x^2 -2 = 0
= x = -,+✓2 Ans.
Similar questions