Question

(x+1/x)^2-(x-1/x)^2=?​

Answer 1

{(x + \{1}{x}) }^{2} + {(x - \{1}{x}) }^{2} \\ = {x}^{2} + { (\{1}{x} )}^{2} + 2 \x \\{1}{x} + {x}^{2} + { (\{1}{x}) }^{2} - 2 x \{1}{x} \\ = 2 {x}^{2} + \{2}{ {x}^{2} } \\ = \{2 {x}^{4} + 2 }{ {x}^{2} }

(x+

x

1

)

2

+(x−

x

1

)

2

=x

2

+(

x

1

)

2

+2×x×

x

1

+x

2

+(

x

1

)

2

−2×x×

x

1

=2x

2

+

x

2

2

=

x

2

2x

4

+2

Answer 2

Answer:

4

Step-by-step explanation:

=(x+1/x)^2-(x-1/x)^2

= x^2+(1/x)^2+2×x×1/x-x^2-(1/x)^2+2×x×1/x

=2+2

=4 is ans