(x+1)(x+2)-(x+2)(x+3) solve this problem
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1
Answer:
It is an expression, not an equation. An equation would have this expression to be some value, and its solution would be arrived by finding the value for x. You can simplify this though.
Allow (x−2)=y
(x−1)(x−2)(x−3)⟹(y+1)×y×(y−1)
⟹y(y2−1)
⟹y3−y
⟹(x−2)3−(x−2)
⟹(x3−6x2+12x−8)−(x−2)
x3−6x2+11x−6
Answered by
1
Allow (x−2)=y
(x−1)(x−2)(x−3)⟹(y+1)×y×(y−1)
⟹y(y2−1)
⟹y3−y
⟹(x−2)3−(x−2)
⟹(x3−6x2+12x−8)−(x−2)
x3−6x2+11x−6
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