Question

(x+1)(x+2)(x+3)(x+4)+1=0​

Answer 1

Answer:

x^4+10x^3+50x^2+50x+25

Step-by-step explanation:

(x+1)(x+2)(x+3)(x+4)+1=0

= (x^2+2x+x+2)(x^2+4x+3x+12)+1

= (x^2+3x+2)(x^2+7x+12)+1

= x^4+7x^3+12x^2+3x^3+21x^2+36x+2x^2+14x+24+1

= x^4+10x^3+50x^2+50x+24+1

= x^4+10x^3+50x^2+50x+25

I hope it will be help full for u