Question

(x+1)(x+2)(x+3)(x+4)+1=0
please answer fast​

Answer 1

Answer:

{-5+√(5)} {-5-√(5)}

_______ and ______

2. 2

Step-by-step explanation:

(x+1)(x+2)(x+3)(x+4)+1 = 0

(x²+3x+2)(x²+7x+12) + 1 = 0

x⁴+ 10x³ + 35x² + 50x + 25 = 0

(x² + 5x + 5)²= 0

Taking square root on both sides

x² + 5x + 5 = 0

x = (-5 (±) √(25-20)}/2

x = {-5±√5}/2

x = {-5-√(5)}/2 and {-5+√(5)}/2

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