Question

(X+1) (x+2) (x+3)(x+4)= 120​

Answer 1

Answer:

(X+1)(X+4)(X+2)(X+3)=120

(X²+5X+4)(X²+5X+6)=120

Let x²+5x=t

(t+4)(t+6)=120

t²+10t+24=120

t²+10t-96=0

t²+16t-6t-96=0

t(t+16)-6(t+16)=0

(t-6)(t+16)=0,when (t-6)=0

(x²+5x-6)=0

(x²+6x-x-6)=0

x(x+6)-(x+6)=0

(x-1)(x+6)=0 ,x=1,-6

When (t+16)=0

(x²+5x+16)=0

X=(-5±√25−64)/2 =(-5±√−39)/2

The real value of of x =1,-6

and imaginary value of x =(-5+√-39)/2 and (-5-√-39)/2.

Hope it helps you.