Question

(x-1)(x-2)(x-3)(x-4)=15

Answer 1

[10010001001]....Hello user.....[0100010010]
Here's your answer....

Here's a little trick to questions like these.
Try to look for common terms which you can get by addition and multiplication.
Like here, 1 and 4, and 2 and 3 add up to 5, so we will multiply these two pairs with wach other.

(x^2-5x+4)(x^2-5x+6)=15
Now we can assume x^2-5x as y. It will make the equation and are lives a lot simpler.
(y+4)(y+6)=15
y^2+10y+24=15
y^2+10y+9=0
(y+1)(y+9)=0
y= -1 or -9
x^2-5x+9=0 or x^2-5x+1=0
Now, we use the quadratic formula (this is going to be long and tiring)
x = (5 + or - root 11 i)/2
or (5 + or - root 21)/2

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Answer 2

Answer:

hope it will helpful to u!!!!!!!