Question

x-1/x-2+x-3/x-4=25/8​

Answer 1

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• $\dfrac{x-1}{x-2}+\dfrac{x-3}{x-4}=\dfrac{25}{8}$

• $\dfrac{(x-1)(x-4)+(x-3)(x-2)}{(x-2)(x-4)}=\dfrac{25}{8}$

• $\dfrac{x^2-5x+4+x^2-5x+6}{x^2-6x+8}=\dfrac{25}{8}$

• $\dfrac{2x^2-10x+10}{x^2-6x+8}=\dfrac{25}{8}$

• $\dfrac{8(2x^2-10x+10)}{25(x^2-6x+8)}=1$

• $16x^2-80x+80=25x^2-150x+200$

• $9x^2-70x+130=0$

• x = (35±√55 )/9