Question

(x+1)(x+2)(x+3)(x+4)-48=0. Find the roots of this equation​

Answer 1

Step-by-step explanation:

$(x + 1)(x +2 )(x + 3)(x + 4) = 48 \\ taking \: 48 \: on \: other \: side... \\ \\ therefore \: by \: comparing....$

calculate the value