Math, asked by halarizwan, 6 months ago

(x+1)(x+2)(x+3)(x+4)-48=0. Find the roots of this equation

Answers

Answered by samvabyav0

0

Step-by-step explanation:

$(x + 1)(x +2 )(x + 3)(x + 4) = 48 \\ taking \: 48 \: on \: other \: side... \\ \\ therefore \: by \: comparing.... \\$

calculate the value

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