Question

(x+1)(x+2)(x+3)(x+4)(x+5) then the value of x=?

Answer 1

(X+1)(X+2)(X+3)(X+4)(X+5)
=($x^{2}$+2X+X+2)(X+3)(X+4)(X+5)
=($x^{3}$+$3 x^{2}$+$2 x^{2}$+6X+$x^{2} +3X+2X+6$)(X+4)(X+5)
=($x^{4} +4 x^{3} +3 x^{3} +12 x^{2} +2 x^{3} +8 x^{2} +6 x^{2} +24 x+ x^{3} +4 x^{2} +3 x^{2} +12 x$+$2 x^{2} +8 x+6 x+24$)(X+5)
=$x^{5}+5 x^{4}+4 x^{4} +20 x^{3} +3 x^{4} +15 x^{3} +12 x^{3} +60 x^{2} +2 x^{4} +10 x^{3} +8 x^{3}$+$40 x^{2} +6 x^{3}+30 x^{2} +24 x^{2} +120 x+ x^{4} +5 x^{3} +4 x^{3}+20 x^{2} +3 x^{3}$+$15 x^{2} +12 x^{2} +60 x+2 x^{3} +10 x^{2} +8 x^{2} +40 x+6 x^{2} +30 +24 x +120$
=$x^{5} +15 x^{4} +85 x^{3} +225 x^{2} +274 x+120$