Question

(x+1)(x+2)(x+3)(x+6)-3x^2​

Answer 1

Answer:

way to do it is to write (x+2)(x+3)=x2+6x+6−x, (x+1)(x+6)=x2+6x+6+x, so

(x+2)(x+3)(x+1)(x+6)=(x2+6x+6)2−x2

which gives that

(x+2)(x+3)(x+1)(x+6)−3x2=(x2+6x