Question

X-1 ,x+2 ,x-7 , are in A. P find the value of x

Answer 1

$given\\ x - 1 \: \: \: \: x + 2 \: \: \: \: x - 7 \: \\ are \: in \: ap \\ = > 2(x + 2) = x - 1 + x - 7 \\ = > 2x + 4 = 2x - 8 \\ divide \: with \: x \\ 2 + \frac{4}{x} = 2 - \frac{8}{x} \\ = > \frac{12}{x} = 0 \\ = > x = \frac{12}{0} = \frac{1}{0}$

hope it helps