Question

( x-1)(x-2)(x²-9x+4) /(x-7)(x²-3x+2)​

Answer 1

Answer:

Value of X is 2

Step-by-step explanation:

Given,

\frac {(x-1)(x-2)(x^2-9x+14)}{(x-7)(x^2-3x+2)}(x−7)(x2−3x+2)(x−1)(x−2)(x2−9x+14)

= \frac {(x-1)(x-2)(x^2-7x-2x+14)}{(x-7)(x^2-2x-x+2)}(x−7)(x2−2x−x+2)(x−1)(x−2)(x2−7x−2x+14)

= \frac {(x-1)(x-2)(x(x-7)-2(x-7))}{(x-7)(x(x-2)-1(x-2))}(x−7)(x(x−2)−1(x−2))(x−1)(x−2)(x(x−7)−2(x−7))

= \frac {(x-1)(x-2)(x-2)(x-7)}{(x-7)(x-1)(x-2)}(x−7)(x−1)(x−2)(x−1)(x−2)(x−2)(x−7)

= x-2

Now, Putting the value of x in an equation-

Let x-2 = 0

x=2