Question

x+1/x = 2cos20 then value of xcube and 1/xcube is?

Answer 1

Step-by-step explanation:

If x+1/x=2cosA, what is the value of x³+1/x³?

x + 1/x = 2 cosA.

We know that a^3+b^3 = (a+b)^3–3ab(a+b)

So (x^3 + 1/x^3)=(x + 1/x)^3 -3×x×(1/x)(x + 1/x)

= (2cosA)^3 - 3×2cosA = 8cos^3A - 6cosA

= 2(4cos^3A - 3cosA) = 2cos3A . (Since cos3A = 4cos^3A-3cosA).

If x+1x=a , what is x2+1x2 ?

If x+1/x=3, then what is the value of x³+1/x³=?

What is the value of x, when x³⁼π+1?

If x²+√x-√1-x=2, then what is the value of x?

If (x+1/x)=2, what is the value of (x-1/x)?

x+1x=2cosA

x3+1x3=(x+1x)3−3(x+1x)

=8cos3A−6cosA=2.(4cos3A−3cosA)

=2cos3A

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